Fermat's Last Theorem (trivial case)
There are no natural numbers a, b such that an + bn = cn, where n>2 is odd and c is a prime number.
Proof. an + bn = ( an-1 - an-2b + ... - abn-2 + bn-1 )( a + b ) = cn.
max(a,b) < c < a+b = cd, but max(a,b)2 > a+b.
Proof. an + bn = ( an-1 - an-2b + ... - abn-2 + bn-1 )( a + b ) = cn.
max(a,b) < c < a+b = cd, but max(a,b)2 > a+b.
Labels: 22, mathematik
Eingetragen Am/um
16:53
